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12581660233 is a prime number
BaseRepresentation
bin10111011011110110…
…01110011001001001
31012110211121120012001
423231323032121021
5201231401111413
65440244351001
7623533230112
oct135573163111
935424546161
1012581660233
11537702360a
1225316a5461
13125680b88c
14874d8d209
154d98694dd
hex2edece649

12581660233 has 2 divisors, whose sum is σ = 12581660234. Its totient is φ = 12581660232.

The previous prime is 12581660213. The next prime is 12581660243. The reversal of 12581660233 is 33206618521.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12581660224 + 9 = 112168^2 + 3^2 .

It is an emirp because it is prime and its reverse (33206618521) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12581660233 is a prime.

It is a super-2 number, since 2×125816602332 (a number of 21 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12581660192 and 12581660201.

It is not a weakly prime, because it can be changed into another prime (12581660213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6290830116 + 6290830117.

It is an arithmetic number, because the mean of its divisors is an integer number (6290830117).

Almost surely, 212581660233 is an apocalyptic number.

It is an amenable number.

12581660233 is a deficient number, since it is larger than the sum of its proper divisors (1).

12581660233 is an equidigital number, since it uses as much as digits as its factorization.

12581660233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 51840, while the sum is 37.

The spelling of 12581660233 in words is "twelve billion, five hundred eighty-one million, six hundred sixty thousand, two hundred thirty-three".