Base | Representation |
---|---|
bin | 10111011101000000… |
… | …00100000000101001 |
3 | 1012111111210011211022 |
4 | 23232200010000221 |
5 | 201241334121113 |
6 | 5441231342225 |
7 | 624011300051 |
oct | 135640040051 |
9 | 35444704738 |
10 | 12591317033 |
11 | 5381519939 |
12 | 2534981975 |
13 | 1258810169 |
14 | 876384561 |
15 | 4da625908 |
hex | 2ee804029 |
12591317033 has 2 divisors, whose sum is σ = 12591317034. Its totient is φ = 12591317032.
The previous prime is 12591317017. The next prime is 12591317047. The reversal of 12591317033 is 33071319521.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10117945744 + 2473371289 = 100588^2 + 49733^2 .
It is an emirp because it is prime and its reverse (33071319521) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12591317033 - 24 = 12591317017 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12591316984 and 12591317002.
It is not a weakly prime, because it can be changed into another prime (12591317093) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6295658516 + 6295658517.
It is an arithmetic number, because the mean of its divisors is an integer number (6295658517).
Almost surely, 212591317033 is an apocalyptic number.
It is an amenable number.
12591317033 is a deficient number, since it is larger than the sum of its proper divisors (1).
12591317033 is an equidigital number, since it uses as much as digits as its factorization.
12591317033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 17010, while the sum is 35.
The spelling of 12591317033 in words is "twelve billion, five hundred ninety-one million, three hundred seventeen thousand, thirty-three".
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