Base | Representation |
---|---|
bin | 11100101001110001110111… |
… | …100000100110110100011001 |
3 | 121112012001012210021001211212 |
4 | 130221301313200212310121 |
5 | 113004122433422012303 |
6 | 1124003035424432505 |
7 | 35354244342154145 |
oct | 3451616740466431 |
9 | 545161183231755 |
10 | 126016345500953 |
11 | 37175260883436 |
12 | 1217298b178735 |
13 | 55413a0cb210b |
14 | 231931ba4a225 |
15 | e87e935cead8 |
hex | 729c77826d19 |
126016345500953 has 2 divisors, whose sum is σ = 126016345500954. Its totient is φ = 126016345500952.
The previous prime is 126016345500911. The next prime is 126016345501049. The reversal of 126016345500953 is 359005543610621.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 114501813104704 + 11514532396249 = 10700552^2 + 3393307^2 .
It is an emirp because it is prime and its reverse (359005543610621) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 126016345500953 - 224 = 126016328723737 is a prime.
It is not a weakly prime, because it can be changed into another prime (126016345500053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63008172750476 + 63008172750477.
It is an arithmetic number, because the mean of its divisors is an integer number (63008172750477).
Almost surely, 2126016345500953 is an apocalyptic number.
It is an amenable number.
126016345500953 is a deficient number, since it is larger than the sum of its proper divisors (1).
126016345500953 is an equidigital number, since it uses as much as digits as its factorization.
126016345500953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2916000, while the sum is 50.
The spelling of 126016345500953 in words is "one hundred twenty-six trillion, sixteen billion, three hundred forty-five million, five hundred thousand, nine hundred fifty-three".
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