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1261013325553 = 3833292462991
BaseRepresentation
bin10010010110011010010…
…000000101011011110001
311110112220012001012001201
4102112122100011123301
5131130023402404203
62403145043531201
7160051041261442
oct22263220053361
94415805035051
101261013325553
1144687a169693
12184486989b01
1391bb3c694c7
14450677d72c9
1522c063a2e1d
hex1259a4056f1

1261013325553 has 4 divisors (see below), whose sum is σ = 1264305788928. Its totient is φ = 1257720862180.

The previous prime is 1261013325461. The next prime is 1261013325571. The reversal of 1261013325553 is 3555233101621.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1261013325553 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1261013322553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1646231113 + ... + 1646231878.

It is an arithmetic number, because the mean of its divisors is an integer number (316076447232).

Almost surely, 21261013325553 is an apocalyptic number.

It is an amenable number.

1261013325553 is a deficient number, since it is larger than the sum of its proper divisors (3292463375).

1261013325553 is an equidigital number, since it uses as much as digits as its factorization.

1261013325553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3292463374.

The product of its (nonzero) digits is 81000, while the sum is 37.

The spelling of 1261013325553 in words is "one trillion, two hundred sixty-one billion, thirteen million, three hundred twenty-five thousand, five hundred fifty-three".

Divisors: 1 383 3292462991 1261013325553