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12613565005577 is a prime number
BaseRepresentation
bin1011011110001101001100…
…0011111011111100001001
31122122211211000212211200122
42313203103003323330021
53123130040120134302
642454331453313025
72441204620344524
oct267432303737411
948584730784618
1012613565005577
114023423679908
1214b8715495775
137065b97b42c3
143186dd665bbb
1516d193ae93a2
hexb78d30fbf09

12613565005577 has 2 divisors, whose sum is σ = 12613565005578. Its totient is φ = 12613565005576.

The previous prime is 12613565005571. The next prime is 12613565005747. The reversal of 12613565005577 is 77550056531621.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10234138439056 + 2379426566521 = 3199084^2 + 1542539^2 .

It is an emirp because it is prime and its reverse (77550056531621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12613565005577 - 236 = 12544845528841 is a prime.

It is a super-2 number, since 2×126135650055772 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12613565005571) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6306782502788 + 6306782502789.

It is an arithmetic number, because the mean of its divisors is an integer number (6306782502789).

Almost surely, 212613565005577 is an apocalyptic number.

It is an amenable number.

12613565005577 is a deficient number, since it is larger than the sum of its proper divisors (1).

12613565005577 is an equidigital number, since it uses as much as digits as its factorization.

12613565005577 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6615000, while the sum is 53.

The spelling of 12613565005577 in words is "twelve trillion, six hundred thirteen billion, five hundred sixty-five million, five thousand, five hundred seventy-seven".