Base | Representation |
---|---|
bin | 1011011110111001110001… |
… | …0001000101000111110011 |
3 | 1122200222200221021022210011 |
4 | 2313232130101011013303 |
5 | 3123324041313343232 |
6 | 42504031053515351 |
7 | 2442110263310251 |
oct | 267563421050763 |
9 | 48628627238704 |
10 | 12625530606067 |
11 | 4028503975635 |
12 | 14baab47a2b57 |
13 | 707775793492 |
14 | 31911688b5d1 |
15 | 16d644322547 |
hex | b7b9c4451f3 |
12625530606067 has 2 divisors, whose sum is σ = 12625530606068. Its totient is φ = 12625530606066.
The previous prime is 12625530606023. The next prime is 12625530606083. The reversal of 12625530606067 is 76060603552621.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12625530606067 - 243 = 3829437583859 is a prime.
It is a super-3 number, since 3×126255306060673 (a number of 40 digits) contains 333 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 12625530606067.
It is not a weakly prime, because it can be changed into another prime (12625530606097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6312765303033 + 6312765303034.
It is an arithmetic number, because the mean of its divisors is an integer number (6312765303034).
Almost surely, 212625530606067 is an apocalyptic number.
12625530606067 is a deficient number, since it is larger than the sum of its proper divisors (1).
12625530606067 is an equidigital number, since it uses as much as digits as its factorization.
12625530606067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2721600, while the sum is 49.
The spelling of 12625530606067 in words is "twelve trillion, six hundred twenty-five billion, five hundred thirty million, six hundred six thousand, sixty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.075 sec. • engine limits •