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12633325520163 = 324129867585043
BaseRepresentation
bin1011011111010110110011…
…1000010100010100100011
31122201201211011202222201020
42313311230320110110203
53123441022313121123
642511400345540523
72442504404061315
oct267655470242443
948651734688636
1012633325520163
1140308439a69a7
12150050b1a4743
1370841868b39a
14319655c0b7b5
1516d94d80b7e3
hexb7d6ce14523

12633325520163 has 16 divisors (see below), whose sum is σ = 16914923177856. Its totient is φ = 8386974898560.

The previous prime is 12633325520149. The next prime is 12633325520213. The reversal of 12633325520163 is 36102552333621.

It is not a de Polignac number, because 12633325520163 - 25 = 12633325520131 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12633325520143) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 21301320 + ... + 21886362.

It is an arithmetic number, because the mean of its divisors is an integer number (1057182698616).

Almost surely, 212633325520163 is an apocalyptic number.

12633325520163 is a deficient number, since it is larger than the sum of its proper divisors (4281597657693).

12633325520163 is a wasteful number, since it uses less digits than its factorization.

12633325520163 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 615154.

The product of its (nonzero) digits is 583200, while the sum is 42.

Adding to 12633325520163 its reverse (36102552333621), we get a palindrome (48735877853784).

The spelling of 12633325520163 in words is "twelve trillion, six hundred thirty-three billion, three hundred twenty-five million, five hundred twenty thousand, one hundred sixty-three".

Divisors: 1 3 241 723 29867 89601 585043 1755129 7197947 21593841 140995363 422986089 17473479281 52420437843 4211108506721 12633325520163