Base | Representation |
---|---|
bin | 1011011111011000000000… |
… | …1111110111010111010001 |
3 | 1122201202122211012122112012 |
4 | 2313312000033313113101 |
5 | 3123442204004210423 |
6 | 42511452514312305 |
7 | 2442515431033154 |
oct | 267660017672721 |
9 | 48652584178465 |
10 | 12633650460113 |
11 | 40309a0365111 |
12 | 150059bb88695 |
13 | 70846aaabc47 |
14 | 319687033c9b |
15 | 16d96c0e5078 |
hex | b7d803f75d1 |
12633650460113 has 2 divisors, whose sum is σ = 12633650460114. Its totient is φ = 12633650460112.
The previous prime is 12633650460073. The next prime is 12633650460133. The reversal of 12633650460113 is 31106405633621.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12175305211969 + 458345248144 = 3489313^2 + 677012^2 .
It is a cyclic number.
It is not a de Polignac number, because 12633650460113 - 234 = 12616470590929 is a prime.
It is not a weakly prime, because it can be changed into another prime (12633650460133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6316825230056 + 6316825230057.
It is an arithmetic number, because the mean of its divisors is an integer number (6316825230057).
Almost surely, 212633650460113 is an apocalyptic number.
It is an amenable number.
12633650460113 is a deficient number, since it is larger than the sum of its proper divisors (1).
12633650460113 is an equidigital number, since it uses as much as digits as its factorization.
12633650460113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 233280, while the sum is 41.
The spelling of 12633650460113 in words is "twelve trillion, six hundred thirty-three billion, six hundred fifty million, four hundred sixty thousand, one hundred thirteen".
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