Base | Representation |
---|---|
bin | 1011011111011010111110… |
… | …0110000111000111011001 |
3 | 1122201211201011221100202001 |
4 | 2313312233212013013121 |
5 | 3124000320333232303 |
6 | 42512103412241001 |
7 | 2442544215012034 |
oct | 267665746070731 |
9 | 48654634840661 |
10 | 12634444820953 |
11 | 40312687a417a |
12 | 1500782010161 |
13 | 708566539147 |
14 | 31972073201b |
15 | 16d9b6c0631d |
hex | b7daf9871d9 |
12634444820953 has 2 divisors, whose sum is σ = 12634444820954. Its totient is φ = 12634444820952.
The previous prime is 12634444820917. The next prime is 12634444820999. The reversal of 12634444820953 is 35902844443621.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 12468264667849 + 166180153104 = 3531043^2 + 407652^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12634444820953 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12634444820894 and 12634444820903.
It is not a weakly prime, because it can be changed into another prime (12634444820353) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6317222410476 + 6317222410477.
It is an arithmetic number, because the mean of its divisors is an integer number (6317222410477).
Almost surely, 212634444820953 is an apocalyptic number.
It is an amenable number.
12634444820953 is a deficient number, since it is larger than the sum of its proper divisors (1).
12634444820953 is an equidigital number, since it uses as much as digits as its factorization.
12634444820953 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 19906560, while the sum is 55.
The spelling of 12634444820953 in words is "twelve trillion, six hundred thirty-four billion, four hundred forty-four million, eight hundred twenty thousand, nine hundred fifty-three".
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