Search a number
-
+
12634444820953 is a prime number
BaseRepresentation
bin1011011111011010111110…
…0110000111000111011001
31122201211201011221100202001
42313312233212013013121
53124000320333232303
642512103412241001
72442544215012034
oct267665746070731
948654634840661
1012634444820953
1140312687a417a
121500782010161
13708566539147
1431972073201b
1516d9b6c0631d
hexb7daf9871d9

12634444820953 has 2 divisors, whose sum is σ = 12634444820954. Its totient is φ = 12634444820952.

The previous prime is 12634444820917. The next prime is 12634444820999. The reversal of 12634444820953 is 35902844443621.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12468264667849 + 166180153104 = 3531043^2 + 407652^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12634444820953 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12634444820894 and 12634444820903.

It is not a weakly prime, because it can be changed into another prime (12634444820353) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6317222410476 + 6317222410477.

It is an arithmetic number, because the mean of its divisors is an integer number (6317222410477).

Almost surely, 212634444820953 is an apocalyptic number.

It is an amenable number.

12634444820953 is a deficient number, since it is larger than the sum of its proper divisors (1).

12634444820953 is an equidigital number, since it uses as much as digits as its factorization.

12634444820953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 19906560, while the sum is 55.

The spelling of 12634444820953 in words is "twelve trillion, six hundred thirty-four billion, four hundred forty-four million, eight hundred twenty thousand, nine hundred fifty-three".