126400343354113 has 2 divisors, whose sum is σ = 126400343354114. Its totient is φ = 126400343354112.

The previous prime is 126400343354081. The next prime is 126400343354179. The reversal of 126400343354113 is 311453343004621.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 110073838425664 + 16326504928449 = 10491608^2 + 4040607^2 .

It is an emirp because it is prime and its reverse (311453343004621) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 126400343354113 - 2⁵ = 126400343354081 is a prime.

It is not a weakly prime, because it can be changed into another prime (126400343354213) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63200171677056 + 63200171677057.

It is an arithmetic number, because the mean of its divisors is an integer number (63200171677057).

Almost surely, 2^{126400343354113} is an apocalyptic number.

It is an amenable number.

126400343354113 is a deficient number, since it is larger than the sum of its proper divisors (1).

126400343354113 is an equidigital number, since it uses as much as digits as its factorization.

126400343354113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 311040, while the sum is 40.

Adding to 126400343354113 its reverse (311453343004621), we get a palindrome (437853686358734).

The spelling of 126400343354113 in words is "one hundred twenty-six trillion, four hundred billion, three hundred forty-three million, three hundred fifty-four thousand, one hundred thirteen".