Base | Representation |
---|---|
bin | 11100101111010111011111… |
… | …100100001010101100001001 |
3 | 121120112202101020222011010210 |
4 | 130233113133210022230021 |
5 | 113031420400344312441 |
6 | 1124455303251231333 |
7 | 35424060225103644 |
oct | 3457273744125411 |
9 | 546482336864123 |
10 | 126400343354121 |
11 | 373030a2633aa1 |
12 | 122152972a8549 |
13 | 556b669295005 |
14 | 232db4887ca5b |
15 | e92e6a20b616 |
hex | 72f5df90ab09 |
126400343354121 has 16 divisors (see below), whose sum is σ = 171722188715904. Its totient is φ = 82672854461184.
The previous prime is 126400343354113. The next prime is 126400343354179. The reversal of 126400343354121 is 121453343004621.
It is not a de Polignac number, because 126400343354121 - 23 = 126400343354113 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 126400343354121.
It is not an unprimeable number, because it can be changed into a prime (126400343334121) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16491781 + ... + 22908066.
It is an arithmetic number, because the mean of its divisors is an integer number (10732636794744).
Almost surely, 2126400343354121 is an apocalyptic number.
It is an amenable number.
126400343354121 is a deficient number, since it is larger than the sum of its proper divisors (45321845361783).
126400343354121 is a wasteful number, since it uses less digits than its factorization.
126400343354121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39420080.
The product of its (nonzero) digits is 207360, while the sum is 39.
Adding to 126400343354121 its reverse (121453343004621), we get a palindrome (247853686358742).
The spelling of 126400343354121 in words is "one hundred twenty-six trillion, four hundred billion, three hundred forty-three million, three hundred fifty-four thousand, one hundred twenty-one".
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