Base | Representation |
---|---|
bin | 10111100011000110… |
… | …10111000111000011 |
3 | 1012122002010012222002 |
4 | 23301203113013003 |
5 | 201342440411342 |
6 | 5450300534215 |
7 | 625202406332 |
oct | 136143270703 |
9 | 35562105862 |
10 | 12642513347 |
11 | 53a8407442 |
12 | 2549b5136b |
13 | 12662c6c39 |
14 | 87d0add19 |
15 | 4ded89d32 |
hex | 2f18d71c3 |
12642513347 has 2 divisors, whose sum is σ = 12642513348. Its totient is φ = 12642513346.
The previous prime is 12642513319. The next prime is 12642513353. The reversal of 12642513347 is 74331524621.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12642513347 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12642513347.
It is not a weakly prime, because it can be changed into another prime (12642513307) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6321256673 + 6321256674.
It is an arithmetic number, because the mean of its divisors is an integer number (6321256674).
Almost surely, 212642513347 is an apocalyptic number.
12642513347 is a deficient number, since it is larger than the sum of its proper divisors (1).
12642513347 is an equidigital number, since it uses as much as digits as its factorization.
12642513347 is an evil number, because the sum of its binary digits is even.
The product of its digits is 120960, while the sum is 38.
The spelling of 12642513347 in words is "twelve billion, six hundred forty-two million, five hundred thirteen thousand, three hundred forty-seven".
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