Base | Representation |
---|---|
bin | 10111100011010110… |
… | …00001000100110011 |
3 | 1012122012220011220120 |
4 | 23301223001010303 |
5 | 201343444121433 |
6 | 5450411541323 |
7 | 625225435335 |
oct | 136153010463 |
9 | 35565804816 |
10 | 12644520243 |
11 | 53a9558233 |
12 | 254a75a843 |
13 | 126684a554 |
14 | 87d473455 |
15 | 4e01347b3 |
hex | 2f1ac1133 |
12644520243 has 4 divisors (see below), whose sum is σ = 16859360328. Its totient is φ = 8429680160.
The previous prime is 12644520199. The next prime is 12644520247. The reversal of 12644520243 is 34202544621.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12644520243 - 213 = 12644512051 is a prime.
It is a super-3 number, since 3×126445202433 (a number of 31 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (12644520247) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2107420038 + ... + 2107420043.
It is an arithmetic number, because the mean of its divisors is an integer number (4214840082).
Almost surely, 212644520243 is an apocalyptic number.
12644520243 is a deficient number, since it is larger than the sum of its proper divisors (4214840085).
12644520243 is an equidigital number, since it uses as much as digits as its factorization.
12644520243 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4214840084.
The product of its (nonzero) digits is 46080, while the sum is 33.
The spelling of 12644520243 in words is "twelve billion, six hundred forty-four million, five hundred twenty thousand, two hundred forty-three".
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