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12648803527153 is a prime number
BaseRepresentation
bin1011100000010000011101…
…1100001110100111110001
31122210012202212101012201101
42320010013130032213301
53124214222200332103
642522440301204401
72443563100005163
oct270040734164761
948705685335641
1012648803527153
114037366923712
12150350a860701
13709a1425bbc1
1431a2c3700933
1516e057592a1d
hexb810770e9f1

12648803527153 has 2 divisors, whose sum is σ = 12648803527154. Its totient is φ = 12648803527152.

The previous prime is 12648803527111. The next prime is 12648803527169. The reversal of 12648803527153 is 35172530884621.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12617641745424 + 31161781729 = 3552132^2 + 176527^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12648803527153 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 12648803527094 and 12648803527103.

It is not a weakly prime, because it can be changed into another prime (12648803527103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6324401763576 + 6324401763577.

It is an arithmetic number, because the mean of its divisors is an integer number (6324401763577).

Almost surely, 212648803527153 is an apocalyptic number.

It is an amenable number.

12648803527153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12648803527153 is an equidigital number, since it uses as much as digits as its factorization.

12648803527153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9676800, while the sum is 55.

The spelling of 12648803527153 in words is "twelve trillion, six hundred forty-eight billion, eight hundred three million, five hundred twenty-seven thousand, one hundred fifty-three".