Base | Representation |
---|---|
bin | 10111100100001001… |
… | …00101010001110010 |
3 | 1012122200111200011121 |
4 | 23302010211101302 |
5 | 201402203102010 |
6 | 5451211332454 |
7 | 625336420351 |
oct | 136204452162 |
9 | 35580450147 |
10 | 12651222130 |
11 | 5402315488 |
12 | 2550a5112a |
13 | 1268055b71 |
14 | 8802d9998 |
15 | 4e0a0a3da |
hex | 2f2125472 |
12651222130 has 16 divisors (see below), whose sum is σ = 22795058520. Its totient is φ = 5055409152.
The previous prime is 12651222083. The next prime is 12651222139. The reversal of 12651222130 is 3122215621.
It can be written as a sum of positive squares in 4 ways, for example, as 10018608649 + 2632613481 = 100093^2 + 51309^2 .
It is a super-3 number, since 3×126512221303 (a number of 31 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12651222095 and 12651222104.
It is not an unprimeable number, because it can be changed into a prime (12651222139) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 624495 + ... + 644434.
Almost surely, 212651222130 is an apocalyptic number.
12651222130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12651222130 is a deficient number, since it is larger than the sum of its proper divisors (10143836390).
12651222130 is a wasteful number, since it uses less digits than its factorization.
12651222130 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1269933.
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 12651222130 its reverse (3122215621), we get a palindrome (15773437751).
The spelling of 12651222130 in words is "twelve billion, six hundred fifty-one million, two hundred twenty-two thousand, one hundred thirty".
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