Base | Representation |
---|---|
bin | 10111100100110001… |
… | …00001101001000001 |
3 | 1012200001100021121121 |
4 | 23302120201221001 |
5 | 201410022400423 |
6 | 5451515352241 |
7 | 625432023316 |
oct | 136230415101 |
9 | 35601307547 |
10 | 12656450113 |
11 | 540526632a |
12 | 2552752681 |
13 | 1269166648 |
14 | 880c9ad0d |
15 | 4e11de45d |
hex | 2f2621a41 |
12656450113 has 4 divisors (see below), whose sum is σ = 12753064368. Its totient is φ = 12559835860.
The previous prime is 12656450111. The next prime is 12656450123. The reversal of 12656450113 is 31105465621.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 31105465621 = 58979 ⋅527399.
It is a cyclic number.
It is not a de Polignac number, because 12656450113 - 21 = 12656450111 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12656450111) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 48306931 + ... + 48307192.
It is an arithmetic number, because the mean of its divisors is an integer number (3188266092).
Almost surely, 212656450113 is an apocalyptic number.
It is an amenable number.
12656450113 is a deficient number, since it is larger than the sum of its proper divisors (96614255).
12656450113 is an equidigital number, since it uses as much as digits as its factorization.
12656450113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 96614254.
The product of its (nonzero) digits is 21600, while the sum is 34.
The spelling of 12656450113 in words is "twelve billion, six hundred fifty-six million, four hundred fifty thousand, one hundred thirteen".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •