126634402516553 has 4 divisors (see below), whose sum is σ = 126634741536768. Its totient is φ = 126634063496340.

The previous prime is 126634402516549. The next prime is 126634402516561. The reversal of 126634402516553 is 355615204436621.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 126634402516553 - 2² = 126634402516549 is a prime.

It is a super-3 number, since 3×126634402516553³ (a number of 43 digits) contains 333 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 126634402516495 and 126634402516504.

It is not an unprimeable number, because it can be changed into a prime (126634402536553) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 168949193 + ... + 169697078.

It is an arithmetic number, because the mean of its divisors is an integer number (31658685384192).

Almost surely, 2^{126634402516553} is an apocalyptic number.

It is an amenable number.

126634402516553 is a deficient number, since it is larger than the sum of its proper divisors (339020215).

126634402516553 is an equidigital number, since it uses as much as digits as its factorization.

126634402516553 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 339020214.

The product of its (nonzero) digits is 15552000, while the sum is 53.

The spelling of 126634402516553 in words is "one hundred twenty-six trillion, six hundred thirty-four billion, four hundred two million, five hundred sixteen thousand, five hundred fifty-three".