Base | Representation |
---|---|
bin | 10111100110010100… |
… | …10010011110011001 |
3 | 1012200221220001002201 |
4 | 23303022102132121 |
5 | 201421342321233 |
6 | 5453103130201 |
7 | 625650634525 |
oct | 136312223631 |
9 | 35627801081 |
10 | 12669495193 |
11 | 5411666293 |
12 | 2556ba3961 |
13 | 126ba83224 |
14 | 8828d4d85 |
15 | 4e241977d |
hex | 2f3292799 |
12669495193 has 4 divisors (see below), whose sum is σ = 13011914020. Its totient is φ = 12327076368.
The previous prime is 12669495161. The next prime is 12669495197. The reversal of 12669495193 is 39159496621.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7713757584 + 4955737609 = 87828^2 + 70397^2 .
It is a cyclic number.
It is not a de Polignac number, because 12669495193 - 25 = 12669495161 is a prime.
It is a super-2 number, since 2×126694951932 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12669495197) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 171209358 + ... + 171209431.
It is an arithmetic number, because the mean of its divisors is an integer number (3252978505).
Almost surely, 212669495193 is an apocalyptic number.
It is an amenable number.
12669495193 is a deficient number, since it is larger than the sum of its proper divisors (342418827).
12669495193 is an equidigital number, since it uses as much as digits as its factorization.
12669495193 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 342418826.
The product of its digits is 3149280, while the sum is 55.
The spelling of 12669495193 in words is "twelve billion, six hundred sixty-nine million, four hundred ninety-five thousand, one hundred ninety-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.086 sec. • engine limits •