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12696478043 = 99011282343
BaseRepresentation
bin10111101001100010…
…01110000101011011
31012202211122220121112
423310301032011123
5202000244244133
65455505330535
7626426165654
oct136461160533
935684586545
1012696478043
115425915967
122564036a4b
13127453cb02
1488631a52b
154e4999648
hex2f4c4e15b

12696478043 has 4 divisors (see below), whose sum is σ = 12697770288. Its totient is φ = 12695185800.

The previous prime is 12696478013. The next prime is 12696478049. The reversal of 12696478043 is 34087469621.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12696478043 - 218 = 12696215899 is a prime.

It is a super-2 number, since 2×126964780432 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12696477982 and 12696478000.

It is not an unprimeable number, because it can be changed into a prime (12696478049) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 631271 + ... + 651072.

It is an arithmetic number, because the mean of its divisors is an integer number (3174442572).

Almost surely, 212696478043 is an apocalyptic number.

12696478043 is a deficient number, since it is larger than the sum of its proper divisors (1292245).

12696478043 is an equidigital number, since it uses as much as digits as its factorization.

12696478043 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1292244.

The product of its (nonzero) digits is 1741824, while the sum is 50.

The spelling of 12696478043 in words is "twelve billion, six hundred ninety-six million, four hundred seventy-eight thousand, forty-three".

Divisors: 1 9901 1282343 12696478043