Base | Representation |
---|---|
bin | 10111101001100011… |
… | …00111010101101011 |
3 | 1012202211212011111122 |
4 | 23310301213111223 |
5 | 202000311101413 |
6 | 5455511445455 |
7 | 626430106355 |
oct | 136461472553 |
9 | 35684764448 |
10 | 12696581483 |
11 | 5425986653 |
12 | 256408688b |
13 | 1274577c11 |
14 | 8863460d5 |
15 | 4e49ba108 |
hex | 2f4c6756b |
12696581483 has 4 divisors (see below), whose sum is σ = 12760383600. Its totient is φ = 12632779368.
The previous prime is 12696581377. The next prime is 12696581533. The reversal of 12696581483 is 38418569621.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 38418569621 = 739 ⋅51987239.
It is a cyclic number.
It is not a de Polignac number, because 12696581483 - 216 = 12696515947 is a prime.
It is a super-2 number, since 2×126965814832 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12696583483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 31900760 + ... + 31901157.
It is an arithmetic number, because the mean of its divisors is an integer number (3190095900).
Almost surely, 212696581483 is an apocalyptic number.
12696581483 is a deficient number, since it is larger than the sum of its proper divisors (63802117).
12696581483 is an equidigital number, since it uses as much as digits as its factorization.
12696581483 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 63802116.
The product of its digits is 2488320, while the sum is 53.
The spelling of 12696581483 in words is "twelve billion, six hundred ninety-six million, five hundred eighty-one thousand, four hundred eighty-three".
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