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12706075433 = 13469943357
BaseRepresentation
bin10111101010101011…
…10101001100101001
31012210111201111202102
423311111311030221
5202010223403213
65500451143145
7626603600462
oct136525651451
935714644672
1012706075433
115430280597
1225672a4ab5
13127652033c
148876d7d69
154e5743158
hex2f5575329

12706075433 has 4 divisors (see below), whose sum is σ = 12707032260. Its totient is φ = 12705118608.

The previous prime is 12706075411. The next prime is 12706075463. The reversal of 12706075433 is 33457060721.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 10510965529 + 2195109904 = 102523^2 + 46852^2 .

It is a cyclic number.

It is not a de Polignac number, because 12706075433 - 28 = 12706075177 is a prime.

It is a super-2 number, since 2×127060754332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12706075463) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 458210 + ... + 485147.

It is an arithmetic number, because the mean of its divisors is an integer number (3176758065).

Almost surely, 212706075433 is an apocalyptic number.

It is an amenable number.

12706075433 is a deficient number, since it is larger than the sum of its proper divisors (956827).

12706075433 is an equidigital number, since it uses as much as digits as its factorization.

12706075433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 956826.

The product of its (nonzero) digits is 105840, while the sum is 38.

The spelling of 12706075433 in words is "twelve billion, seven hundred six million, seventy-five thousand, four hundred thirty-three".

Divisors: 1 13469 943357 12706075433