12710389243 has 4 divisors (see below), whose sum is σ = 12713530888. Its totient is φ = 12707247600.

The previous prime is 12710389229. The next prime is 12710389247. The reversal of 12710389243 is 34298301721.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12710389243 is a prime.

It is a super-2 number, since 2×12710389243² (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12710389196 and 12710389205.

It is not an unprimeable number, because it can be changed into a prime (12710389247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1564746 + ... + 1572847.

It is an arithmetic number, because the mean of its divisors is an integer number (3178382722).

Almost surely, 2^12710389243 is an apocalyptic number.

12710389243 is a deficient number, since it is larger than the sum of its proper divisors (3141645).

12710389243 is an equidigital number, since it uses as much as digits as its factorization.

12710389243 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3141644.

The product of its (nonzero) digits is 72576, while the sum is 40.

The spelling of 12710389243 in words is "twelve billion, seven hundred ten million, three hundred eighty-nine thousand, two hundred forty-three".