12711611531449 has 2 divisors, whose sum is σ = 12711611531450. Its totient is φ = 12711611531448.

The previous prime is 12711611531431. The next prime is 12711611531519. The reversal of 12711611531449 is 94413511611721.

12711611531449 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11778919153849 + 932692377600 = 3432043^2 + 965760^2 .

It is an emirp because it is prime and its reverse (94413511611721) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12711611531449 - 2¹¹ = 12711611529401 is a prime.

It is a super-2 number, since 2×12711611531449² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 12711611531399 and 12711611531408.

It is not a weakly prime, because it can be changed into another prime (12711611535449) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6355805765724 + 6355805765725.

It is an arithmetic number, because the mean of its divisors is an integer number (6355805765725).

Almost surely, 2^{12711611531449} is an apocalyptic number.

It is an amenable number.

12711611531449 is a deficient number, since it is larger than the sum of its proper divisors (1).

12711611531449 is an equidigital number, since it uses as much as digits as its factorization.

12711611531449 is an evil number, because the sum of its binary digits is even.

The product of its digits is 181440, while the sum is 46.

The spelling of 12711611531449 in words is "twelve trillion, seven hundred eleven billion, six hundred eleven million, five hundred thirty-one thousand, four hundred forty-nine".