Base | Representation |
---|---|
bin | 1011100011111010011100… |
… | …0101110111010110110001 |
3 | 1200000012220001202221021202 |
4 | 2320332213011313112301 |
5 | 3131231340024431033 |
6 | 43011344515300545 |
7 | 2451245404332503 |
oct | 270764705672661 |
9 | 50005801687252 |
10 | 12711611561393 |
11 | 4060a67376428 |
12 | 1513718baa755 |
13 | 71291369a1c4 |
14 | 31d3610a9d73 |
15 | 1709d15ba8e8 |
hex | b8fa71775b1 |
12711611561393 has 2 divisors, whose sum is σ = 12711611561394. Its totient is φ = 12711611561392.
The previous prime is 12711611561387. The next prime is 12711611561461. The reversal of 12711611561393 is 39316511611721.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 8910893652544 + 3800717908849 = 2985112^2 + 1949543^2 .
It is an emirp because it is prime and its reverse (39316511611721) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12711611561393 - 24 = 12711611561377 is a prime.
It is not a weakly prime, because it can be changed into another prime (12711641561393) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6355805780696 + 6355805780697.
It is an arithmetic number, because the mean of its divisors is an integer number (6355805780697).
Almost surely, 212711611561393 is an apocalyptic number.
It is an amenable number.
12711611561393 is a deficient number, since it is larger than the sum of its proper divisors (1).
12711611561393 is an equidigital number, since it uses as much as digits as its factorization.
12711611561393 is an evil number, because the sum of its binary digits is even.
The product of its digits is 204120, while the sum is 47.
The spelling of 12711611561393 in words is "twelve trillion, seven hundred eleven billion, six hundred eleven million, five hundred sixty-one thousand, three hundred ninety-three".
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