Base | Representation |
---|---|
bin | 111011001101010000… |
… | …0000001110100000011 |
3 | 110011012000220002010221 |
4 | 1312122200001310003 |
5 | 4040343402421013 |
6 | 134224331003511 |
7 | 12120541230361 |
oct | 1663240016403 |
9 | 404160802127 |
10 | 127146138883 |
11 | 49a16754025 |
12 | 20784b99597 |
13 | bcb386990a |
14 | 6222464631 |
15 | 349253a08d |
hex | 1d9a801d03 |
127146138883 has 2 divisors, whose sum is σ = 127146138884. Its totient is φ = 127146138882.
The previous prime is 127146138827. The next prime is 127146138887. The reversal of 127146138883 is 388831641721.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 127146138883 - 213 = 127146130691 is a prime.
It is a super-2 number, since 2×1271461388832 (a number of 23 digits) contains 22 as substring.
It is a self number, because there is not a number n which added to its sum of digits gives 127146138883.
It is not a weakly prime, because it can be changed into another prime (127146138887) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63573069441 + 63573069442.
It is an arithmetic number, because the mean of its divisors is an integer number (63573069442).
Almost surely, 2127146138883 is an apocalyptic number.
127146138883 is a deficient number, since it is larger than the sum of its proper divisors (1).
127146138883 is an equidigital number, since it uses as much as digits as its factorization.
127146138883 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 1548288, while the sum is 52.
The spelling of 127146138883 in words is "one hundred twenty-seven billion, one hundred forty-six million, one hundred thirty-eight thousand, eight hundred eighty-three".
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