1272148525433 has 2 divisors, whose sum is σ = 1272148525434. Its totient is φ = 1272148525432.

The previous prime is 1272148525409. The next prime is 1272148525481. The reversal of 1272148525433 is 3345258412721.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 969305228089 + 302843297344 = 984533^2 + 550312^2 .

It is a cyclic number.

It is not a de Polignac number, because 1272148525433 - 2³² = 1267853558137 is a prime.

It is a super-2 number, since 2×1272148525433² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1272148525733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 636074262716 + 636074262717.

It is an arithmetic number, because the mean of its divisors is an integer number (636074262717).

Almost surely, 2^{1272148525433} is an apocalyptic number.

It is an amenable number.

1272148525433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1272148525433 is an equidigital number, since it uses as much as digits as its factorization.

1272148525433 is an evil number, because the sum of its binary digits is even.

The product of its digits is 1612800, while the sum is 47.

The spelling of 1272148525433 in words is "one trillion, two hundred seventy-two billion, one hundred forty-eight million, five hundred twenty-five thousand, four hundred thirty-three".