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1274300315113 = 7229794947171
BaseRepresentation
bin10010100010110010001…
…101111011010111101001
311111211012011212012012011
4102202302031323113221
5131334231340040423
62413223330115521
7161031230650360
oct22426215732751
94454164765164
101274300315113
114514783415a1
12186b7471bba1
13932209320c7
144596830a7d7
1523232ae3b0d
hex128b237b5e9

1274300315113 has 8 divisors (see below), whose sum is σ = 1462702796480. Its totient is φ = 1087487728560.

The previous prime is 1274300315089. The next prime is 1274300315129. The reversal of 1274300315113 is 3115130034721.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1274300315113 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1274300315143) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 397471983 + ... + 397475188.

It is an arithmetic number, because the mean of its divisors is an integer number (182837849560).

Almost surely, 21274300315113 is an apocalyptic number.

It is an amenable number.

1274300315113 is a deficient number, since it is larger than the sum of its proper divisors (188402481367).

1274300315113 is an equidigital number, since it uses as much as digits as its factorization.

1274300315113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 794947407.

The product of its (nonzero) digits is 7560, while the sum is 31.

Adding to 1274300315113 its reverse (3115130034721), we get a palindrome (4389430349834).

The spelling of 1274300315113 in words is "one trillion, two hundred seventy-four billion, three hundred million, three hundred fifteen thousand, one hundred thirteen".

Divisors: 1 7 229 1603 794947171 5564630197 182042902159 1274300315113