Base | Representation |
---|---|
bin | 10010100010110010001… |
… | …101111011010111101001 |
3 | 11111211012011212012012011 |
4 | 102202302031323113221 |
5 | 131334231340040423 |
6 | 2413223330115521 |
7 | 161031230650360 |
oct | 22426215732751 |
9 | 4454164765164 |
10 | 1274300315113 |
11 | 4514783415a1 |
12 | 186b7471bba1 |
13 | 932209320c7 |
14 | 4596830a7d7 |
15 | 23232ae3b0d |
hex | 128b237b5e9 |
1274300315113 has 8 divisors (see below), whose sum is σ = 1462702796480. Its totient is φ = 1087487728560.
The previous prime is 1274300315089. The next prime is 1274300315129. The reversal of 1274300315113 is 3115130034721.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1274300315113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1274300315143) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 397471983 + ... + 397475188.
It is an arithmetic number, because the mean of its divisors is an integer number (182837849560).
Almost surely, 21274300315113 is an apocalyptic number.
It is an amenable number.
1274300315113 is a deficient number, since it is larger than the sum of its proper divisors (188402481367).
1274300315113 is an equidigital number, since it uses as much as digits as its factorization.
1274300315113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 794947407.
The product of its (nonzero) digits is 7560, while the sum is 31.
Adding to 1274300315113 its reverse (3115130034721), we get a palindrome (4389430349834).
The spelling of 1274300315113 in words is "one trillion, two hundred seventy-four billion, three hundred million, three hundred fifteen thousand, one hundred thirteen".
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