Base | Representation |
---|---|
bin | 10010100011000111011… |
… | …110110001110000000011 |
3 | 11111212010001010101112101 |
4 | 102203013132301300003 |
5 | 131340444201204244 |
6 | 2413322552211231 |
7 | 161043122121511 |
oct | 22430736616003 |
9 | 4455101111471 |
10 | 1274657053699 |
11 | 451640749577 |
12 | 187054099b17 |
13 | 93279807523 |
14 | 4599d84d4b1 |
15 | 232540ae0d4 |
hex | 128c77b1c03 |
1274657053699 has 2 divisors, whose sum is σ = 1274657053700. Its totient is φ = 1274657053698.
The previous prime is 1274657053667. The next prime is 1274657053741. The reversal of 1274657053699 is 9963507564721.
It is a weak prime.
It is an emirp because it is prime and its reverse (9963507564721) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1274657053699 - 25 = 1274657053667 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 1274657053699.
It is not a weakly prime, because it can be changed into another prime (1274657057699) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 637328526849 + 637328526850.
It is an arithmetic number, because the mean of its divisors is an integer number (637328526850).
Almost surely, 21274657053699 is an apocalyptic number.
1274657053699 is a deficient number, since it is larger than the sum of its proper divisors (1).
1274657053699 is an equidigital number, since it uses as much as digits as its factorization.
1274657053699 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 85730400, while the sum is 64.
The spelling of 1274657053699 in words is "one trillion, two hundred seventy-four billion, six hundred fifty-seven million, fifty-three thousand, six hundred ninety-nine".
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