Base | Representation |
---|---|
bin | 10111101111110100… |
… | …00010000100001001 |
3 | 1012220111201101110111 |
4 | 23313322002010021 |
5 | 202102233313003 |
6 | 5505025514321 |
7 | 630635505226 |
oct | 136772020411 |
9 | 35814641414 |
10 | 12749119753 |
11 | 5452600407 |
12 | 25797a29a1 |
13 | 1282411756 |
14 | 88d30094d |
15 | 4e93e6e6d |
hex | 2f7e82109 |
12749119753 has 2 divisors, whose sum is σ = 12749119754. Its totient is φ = 12749119752.
The previous prime is 12749119741. The next prime is 12749119763. The reversal of 12749119753 is 35791194721.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 12749119744 + 9 = 112912^2 + 3^2 .
It is a cyclic number.
It is not a de Polignac number, because 12749119753 - 233 = 4159185161 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 12749119697 and 12749119706.
It is not a weakly prime, because it can be changed into another prime (12749119763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6374559876 + 6374559877.
It is an arithmetic number, because the mean of its divisors is an integer number (6374559877).
Almost surely, 212749119753 is an apocalyptic number.
It is an amenable number.
12749119753 is a deficient number, since it is larger than the sum of its proper divisors (1).
12749119753 is an equidigital number, since it uses as much as digits as its factorization.
12749119753 is an evil number, because the sum of its binary digits is even.
The product of its digits is 476280, while the sum is 49.
The spelling of 12749119753 in words is "twelve billion, seven hundred forty-nine million, one hundred nineteen thousand, seven hundred fifty-three".
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