Base | Representation |
---|---|
bin | 1011100110001010011000… |
… | …0000001111010101100011 |
3 | 1200010220121201002011001111 |
4 | 2321202212000033111203 |
5 | 3132400001442441303 |
6 | 43041214424444151 |
7 | 2454114013636126 |
oct | 271424600172543 |
9 | 50126551064044 |
10 | 12750248015203 |
11 | 4076393673a96 |
12 | 151b100319657 |
13 | 7164600c56aa |
14 | 3211885343bd |
15 | 1719e350db6d |
hex | b98a600f563 |
12750248015203 has 2 divisors, whose sum is σ = 12750248015204. Its totient is φ = 12750248015202.
The previous prime is 12750248015189. The next prime is 12750248015237. The reversal of 12750248015203 is 30251084205721.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12750248015203 is a prime.
It is not a weakly prime, because it can be changed into another prime (12750248015503) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6375124007601 + 6375124007602.
It is an arithmetic number, because the mean of its divisors is an integer number (6375124007602).
Almost surely, 212750248015203 is an apocalyptic number.
12750248015203 is a deficient number, since it is larger than the sum of its proper divisors (1).
12750248015203 is an equidigital number, since it uses as much as digits as its factorization.
12750248015203 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 134400, while the sum is 40.
The spelling of 12750248015203 in words is "twelve trillion, seven hundred fifty billion, two hundred forty-eight million, fifteen thousand, two hundred three".
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