Base | Representation |
---|---|
bin | 1011100110001110111110… |
… | …1010001111110100101011 |
3 | 1200011000210211100200201212 |
4 | 2321203233222033310223 |
5 | 3132410014320422021 |
6 | 43041541211103335 |
7 | 2454156440425256 |
oct | 271435752176453 |
9 | 50130724320655 |
10 | 12751483764011 |
11 | 40769681773a3 |
12 | 151b3a6141b4b |
13 | 7165c91256c5 |
14 | 3212646cc09d |
15 | 171a66c5b85b |
hex | b98efa8fd2b |
12751483764011 has 2 divisors, whose sum is σ = 12751483764012. Its totient is φ = 12751483764010.
The previous prime is 12751483764001. The next prime is 12751483764017. The reversal of 12751483764011 is 11046738415721.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12751483764011 - 214 = 12751483747627 is a prime.
It is a super-2 number, since 2×127514837640112 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12751483764017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6375741882005 + 6375741882006.
It is an arithmetic number, because the mean of its divisors is an integer number (6375741882006).
Almost surely, 212751483764011 is an apocalyptic number.
12751483764011 is a deficient number, since it is larger than the sum of its proper divisors (1).
12751483764011 is an equidigital number, since it uses as much as digits as its factorization.
12751483764011 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1128960, while the sum is 50.
The spelling of 12751483764011 in words is "twelve trillion, seven hundred fifty-one billion, four hundred eighty-three million, seven hundred sixty-four thousand, eleven".
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