Base | Representation |
---|---|
bin | 10111110001110100… |
… | …11001110110100011 |
3 | 1012221200110201010112 |
4 | 23320322121312203 |
5 | 202121043310103 |
6 | 5510431321535 |
7 | 631232106401 |
oct | 137072316643 |
9 | 35850421115 |
10 | 12765994403 |
11 | 54610865a8 |
12 | 25833802ab |
13 | 1285a6c456 |
14 | 891654471 |
15 | 4eab2bcd8 |
hex | 2f8e99da3 |
12765994403 has 2 divisors, whose sum is σ = 12765994404. Its totient is φ = 12765994402.
The previous prime is 12765994369. The next prime is 12765994421. The reversal of 12765994403 is 30449956721.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12765994403 - 214 = 12765978019 is a prime.
It is a super-2 number, since 2×127659944032 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12765994103) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6382997201 + 6382997202.
It is an arithmetic number, because the mean of its divisors is an integer number (6382997202).
Almost surely, 212765994403 is an apocalyptic number.
12765994403 is a deficient number, since it is larger than the sum of its proper divisors (1).
12765994403 is an equidigital number, since it uses as much as digits as its factorization.
12765994403 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1632960, while the sum is 50.
The spelling of 12765994403 in words is "twelve billion, seven hundred sixty-five million, nine hundred ninety-four thousand, four hundred three".
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