Base | Representation |
---|---|
bin | 111011011101111010… |
… | …0000010110110000001 |
3 | 110012121222112220021021 |
4 | 1312323310002312001 |
5 | 4043014442042423 |
6 | 134400014025441 |
7 | 12140435610466 |
oct | 1667364026601 |
9 | 405558486237 |
10 | 127705034113 |
11 | 4a183187308 |
12 | 209001a8281 |
13 | c0725a2b57 |
14 | 627678b66d |
15 | 34c663895d |
hex | 1dbbd02d81 |
127705034113 has 2 divisors, whose sum is σ = 127705034114. Its totient is φ = 127705034112.
The previous prime is 127705034081. The next prime is 127705034123. The reversal of 127705034113 is 311430507721.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 100811330064 + 26893704049 = 317508^2 + 163993^2 .
It is a cyclic number.
It is not a de Polignac number, because 127705034113 - 25 = 127705034081 is a prime.
It is not a weakly prime, because it can be changed into another prime (127705034123) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 63852517056 + 63852517057.
It is an arithmetic number, because the mean of its divisors is an integer number (63852517057).
Almost surely, 2127705034113 is an apocalyptic number.
It is an amenable number.
127705034113 is a deficient number, since it is larger than the sum of its proper divisors (1).
127705034113 is an equidigital number, since it uses as much as digits as its factorization.
127705034113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 17640, while the sum is 34.
The spelling of 127705034113 in words is "one hundred twenty-seven billion, seven hundred five million, thirty-four thousand, one hundred thirteen".
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