Base | Representation |
---|---|
bin | 11101000110110010101110… |
… | …010100101100110111000001 |
3 | 121210020122112001110022211022 |
4 | 131012302232110230313001 |
5 | 113234304221231432233 |
6 | 1132131013012555225 |
7 | 35651266232316626 |
oct | 3506625624546701 |
9 | 553218461408738 |
10 | 128010129952193 |
11 | 37873878160465 |
12 | 12435279622b15 |
13 | 56573c390b088 |
14 | 2387a1ac1c34d |
15 | ebec85a98398 |
hex | 746cae52cdc1 |
128010129952193 has 2 divisors, whose sum is σ = 128010129952194. Its totient is φ = 128010129952192.
The previous prime is 128010129952183. The next prime is 128010129952213. The reversal of 128010129952193 is 391259921010821.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 94648323615169 + 33361806337024 = 9728737^2 + 5775968^2 .
It is a cyclic number.
It is not a de Polignac number, because 128010129952193 - 210 = 128010129951169 is a prime.
It is not a weakly prime, because it can be changed into another prime (128010129952183) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64005064976096 + 64005064976097.
It is an arithmetic number, because the mean of its divisors is an integer number (64005064976097).
Almost surely, 2128010129952193 is an apocalyptic number.
It is an amenable number.
128010129952193 is a deficient number, since it is larger than the sum of its proper divisors (1).
128010129952193 is an equidigital number, since it uses as much as digits as its factorization.
128010129952193 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 699840, while the sum is 53.
The spelling of 128010129952193 in words is "one hundred twenty-eight trillion, ten billion, one hundred twenty-nine million, nine hundred fifty-two thousand, one hundred ninety-three".
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