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12803926250641 is a prime number
BaseRepresentation
bin1011101001010010010101…
…1110011101010010010001
31200100001011122011001010111
42322110211132131102101
53134234420110010031
643122013103401321
72461024141260301
oct272244536352221
950301148131114
1012803926250641
114097129630839
1215295a0bb3241
1371b535c08696
143239db57b601
151730d5c6b1b1
hexba52579d491

12803926250641 has 2 divisors, whose sum is σ = 12803926250642. Its totient is φ = 12803926250640.

The previous prime is 12803926250611. The next prime is 12803926250701. The reversal of 12803926250641 is 14605262930821.

12803926250641 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12140548580241 + 663377670400 = 3484329^2 + 814480^2 .

It is a cyclic number.

It is not a de Polignac number, because 12803926250641 - 225 = 12803892696209 is a prime.

It is not a weakly prime, because it can be changed into another prime (12803926250611) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6401963125320 + 6401963125321.

It is an arithmetic number, because the mean of its divisors is an integer number (6401963125321).

Almost surely, 212803926250641 is an apocalyptic number.

It is an amenable number.

12803926250641 is a deficient number, since it is larger than the sum of its proper divisors (1).

12803926250641 is an equidigital number, since it uses as much as digits as its factorization.

12803926250641 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1244160, while the sum is 49.

The spelling of 12803926250641 in words is "twelve trillion, eight hundred three billion, nine hundred twenty-six million, two hundred fifty thousand, six hundred forty-one".