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1281204341993 is a prime number
BaseRepresentation
bin10010101001001101101…
…110101100110011101001
311112111000100000002121102
4102221031232230303221
5131442401302420433
62420324355251145
7161364303135542
oct22511556546351
94474010002542
101281204341993
114543a04a5134
121883808a9ab5
1393a810a4404
14460212034c9
15234d8ca14e8
hex12a4dbacce9

1281204341993 has 2 divisors, whose sum is σ = 1281204341994. Its totient is φ = 1281204341992.

The previous prime is 1281204341917. The next prime is 1281204342133. The reversal of 1281204341993 is 3991434021821.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1270832345344 + 10371996649 = 1127312^2 + 101843^2 .

It is an emirp because it is prime and its reverse (3991434021821) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1281204341993 - 224 = 1281187564777 is a prime.

It is a super-2 number, since 2×12812043419932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1281204340993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 640602170996 + 640602170997.

It is an arithmetic number, because the mean of its divisors is an integer number (640602170997).

Almost surely, 21281204341993 is an apocalyptic number.

It is an amenable number.

1281204341993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1281204341993 is an equidigital number, since it uses as much as digits as its factorization.

1281204341993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 373248, while the sum is 47.

The spelling of 1281204341993 in words is "one trillion, two hundred eighty-one billion, two hundred four million, three hundred forty-one thousand, nine hundred ninety-three".