Base | Representation |
---|---|
bin | 11101001010010011100100… |
… | …000110011001011011010001 |
3 | 121211002201200001111202201021 |
4 | 131022103210012121123101 |
5 | 113302233133341401232 |
6 | 1132433540541435441 |
7 | 36004603655625301 |
oct | 3512234406313321 |
9 | 554081601452637 |
10 | 128251550340817 |
11 | 379571a47246a2 |
12 | 1247401486bb81 |
13 | 56740b9349537 |
14 | 239559dda9601 |
15 | ec61b5575397 |
hex | 74a4e41996d1 |
128251550340817 has 2 divisors, whose sum is σ = 128251550340818. Its totient is φ = 128251550340816.
The previous prime is 128251550340761. The next prime is 128251550340919. The reversal of 128251550340817 is 718043055152821.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 125164206157761 + 3087344183056 = 11187681^2 + 1757084^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-128251550340817 is a prime.
It is not a weakly prime, because it can be changed into another prime (128251550340217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64125775170408 + 64125775170409.
It is an arithmetic number, because the mean of its divisors is an integer number (64125775170409).
Almost surely, 2128251550340817 is an apocalyptic number.
It is an amenable number.
128251550340817 is a deficient number, since it is larger than the sum of its proper divisors (1).
128251550340817 is an equidigital number, since it uses as much as digits as its factorization.
128251550340817 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2688000, while the sum is 52.
The spelling of 128251550340817 in words is "one hundred twenty-eight trillion, two hundred fifty-one billion, five hundred fifty million, three hundred forty thousand, eight hundred seventeen".
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