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12835376603603 is a prime number
BaseRepresentation
bin1011101011000111100000…
…0100000010000111010011
31200110001100110112111201222
42322301320010002013103
53140243322402303403
643144253545515255
72463216411666401
oct272617004020723
950401313474658
1012835376603603
1140a94a8525484
1215336b97a2b2b
137214a88cc1a8
14325342484471
15173d26d84338
hexbac781021d3

12835376603603 has 2 divisors, whose sum is σ = 12835376603604. Its totient is φ = 12835376603602.

The previous prime is 12835376603557. The next prime is 12835376603617. The reversal of 12835376603603 is 30630667353821.

It is a strong prime.

It is an emirp because it is prime and its reverse (30630667353821) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 12835376603603 - 228 = 12835108168147 is a prime.

It is a super-3 number, since 3×128353766036033 (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12835376603683) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6417688301801 + 6417688301802.

It is an arithmetic number, because the mean of its divisors is an integer number (6417688301802).

Almost surely, 212835376603603 is an apocalyptic number.

12835376603603 is a deficient number, since it is larger than the sum of its proper divisors (1).

12835376603603 is an equidigital number, since it uses as much as digits as its factorization.

12835376603603 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 9797760, while the sum is 53.

The spelling of 12835376603603 in words is "twelve trillion, eight hundred thirty-five billion, three hundred seventy-six million, six hundred three thousand, six hundred three".