12838825119793 has 2 divisors, whose sum is σ = 12838825119794. Its totient is φ = 12838825119792.

The previous prime is 12838825119779. The next prime is 12838825119811. The reversal of 12838825119793 is 39791152883821.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9408654426609 + 3430170693184 = 3067353^2 + 1852072^2 .

It is a cyclic number.

It is not a de Polignac number, because 12838825119793 - 2⁵ = 12838825119761 is a prime.

It is a super-3 number, since 3×12838825119793³ (a number of 40 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (12838826119793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6419412559896 + 6419412559897.

It is an arithmetic number, because the mean of its divisors is an integer number (6419412559897).

Almost surely, 2^{12838825119793} is an apocalyptic number.

It is an amenable number.

12838825119793 is a deficient number, since it is larger than the sum of its proper divisors (1).

12838825119793 is an equidigital number, since it uses as much as digits as its factorization.

12838825119793 is an evil number, because the sum of its binary digits is even.

The product of its digits is 52254720, while the sum is 67.

The spelling of 12838825119793 in words is "twelve trillion, eight hundred thirty-eight billion, eight hundred twenty-five million, one hundred nineteen thousand, seven hundred ninety-three".