1283957406678 has 16 divisors (see below), whose sum is σ = 2584270960560. Its totient is φ = 425259777696.

The previous prime is 1283957406673. The next prime is 1283957406689. The reversal of 1283957406678 is 8766047593821.

It is a super-3 number, since 3×1283957406678³ (a number of 37 digits) contains 333 as substring.

It is a Curzon number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1283957406673) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 681505113 + ... + 681506996.

It is an arithmetic number, because the mean of its divisors is an integer number (161516935035).

It is a 1-persistent number, because it is pandigital, but 2⋅1283957406678 = 2567914813356 is not.

Almost surely, 2^{1283957406678} is an apocalyptic number.

1283957406678 is an abundant number, since it is smaller than the sum of its proper divisors (1300313553882).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1283957406678 is a wasteful number, since it uses less digits than its factorization.

1283957406678 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1363012271.

The product of its (nonzero) digits is 121927680, while the sum is 66.

The spelling of 1283957406678 in words is "one trillion, two hundred eighty-three billion, nine hundred fifty-seven million, four hundred six thousand, six hundred seventy-eight".