Base | Representation |
---|---|
bin | 111011110101000010… |
… | …0101000100001100001 |
3 | 110021122001220220010001 |
4 | 1313222010220201201 |
5 | 4101112132302224 |
6 | 135005020340001 |
7 | 12165611424415 |
oct | 1675204504141 |
9 | 407561826101 |
10 | 128481134689 |
11 | 4a541284146 |
12 | 20a980a4601 |
13 | c16730876b |
14 | 630b894d45 |
15 | 351e83e544 |
hex | 1dea128861 |
128481134689 has 2 divisors, whose sum is σ = 128481134690. Its totient is φ = 128481134688.
The previous prime is 128481134681. The next prime is 128481134699. The reversal of 128481134689 is 986431184821.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 127740478464 + 740656225 = 357408^2 + 27215^2 .
It is a cyclic number.
It is not a de Polignac number, because 128481134689 - 23 = 128481134681 is a prime.
It is not a weakly prime, because it can be changed into another prime (128481134681) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 64240567344 + 64240567345.
It is an arithmetic number, because the mean of its divisors is an integer number (64240567345).
Almost surely, 2128481134689 is an apocalyptic number.
It is an amenable number.
128481134689 is a deficient number, since it is larger than the sum of its proper divisors (1).
128481134689 is an equidigital number, since it uses as much as digits as its factorization.
128481134689 is an evil number, because the sum of its binary digits is even.
The product of its digits is 2654208, while the sum is 55.
It can be divided in two parts, 1284811 and 34689, that added together give a triangular number (1319500 = T1624).
The spelling of 128481134689 in words is "one hundred twenty-eight billion, four hundred eighty-one million, one hundred thirty-four thousand, six hundred eighty-nine".
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