Base | Representation |
---|---|
bin | 1011101011111000011001… |
… | …1000101111111100110011 |
3 | 1200111022020011221102212211 |
4 | 2322332012120233330303 |
5 | 3141002212431122024 |
6 | 43154304212432551 |
7 | 2464162565321152 |
oct | 272760630577463 |
9 | 50438204842784 |
10 | 12848501817139 |
11 | 410402335269a |
12 | 1536161318757 |
13 | 7227bac01b31 |
14 | 325c296c5599 |
15 | 1743442bb594 |
hex | baf8662ff33 |
12848501817139 has 2 divisors, whose sum is σ = 12848501817140. Its totient is φ = 12848501817138.
The previous prime is 12848501817127. The next prime is 12848501817149. The reversal of 12848501817139 is 93171810584821.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12848501817139 - 221 = 12848499719987 is a prime.
It is not a weakly prime, because it can be changed into another prime (12848501817149) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6424250908569 + 6424250908570.
It is an arithmetic number, because the mean of its divisors is an integer number (6424250908570).
Almost surely, 212848501817139 is an apocalyptic number.
12848501817139 is a deficient number, since it is larger than the sum of its proper divisors (1).
12848501817139 is an equidigital number, since it uses as much as digits as its factorization.
12848501817139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 3870720, while the sum is 58.
The spelling of 12848501817139 in words is "twelve trillion, eight hundred forty-eight billion, five hundred one million, eight hundred seventeen thousand, one hundred thirty-nine".
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