Base | Representation |
---|---|
bin | 1011101100001111100110… |
… | …0010011011111111011011 |
3 | 1200111220022010221001202202 |
4 | 2323003321202123333123 |
5 | 3141102441022011323 |
6 | 43201214132320415 |
7 | 2464503106065146 |
oct | 273037142337733 |
9 | 50456263831682 |
10 | 12854728703963 |
11 | 410672925a953 |
12 | 15373ba77310b |
13 | 723270ca9b53 |
14 | 32625a6b505d |
15 | 1745aacbed28 |
hex | bb0f989bfdb |
12854728703963 has 2 divisors, whose sum is σ = 12854728703964. Its totient is φ = 12854728703962.
The previous prime is 12854728703941. The next prime is 12854728704047. The reversal of 12854728703963 is 36930782745821.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-12854728703963 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12854728703963.
It is not a weakly prime, because it can be changed into another prime (12854728703263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6427364351981 + 6427364351982.
It is an arithmetic number, because the mean of its divisors is an integer number (6427364351982).
It is a 1-persistent number, because it is pandigital, but 2⋅12854728703963 = 25709457407926 is not.
Almost surely, 212854728703963 is an apocalyptic number.
12854728703963 is a deficient number, since it is larger than the sum of its proper divisors (1).
12854728703963 is an equidigital number, since it uses as much as digits as its factorization.
12854728703963 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 121927680, while the sum is 65.
The spelling of 12854728703963 in words is "twelve trillion, eight hundred fifty-four billion, seven hundred twenty-eight million, seven hundred three thousand, nine hundred sixty-three".
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