Base | Representation |
---|---|
bin | 10010101101010111011… |
… | …000011010010011100001 |
3 | 11112220111221102220020022 |
4 | 102231113120122103201 |
5 | 132031013234112442 |
6 | 2422342530123225 |
7 | 161612612134106 |
oct | 22552730322341 |
9 | 4486457386208 |
10 | 1285661238497 |
11 | 456278285479 |
12 | 189205420515 |
13 | 9431156888c |
14 | 463250ccaad |
15 | 2369a1c83d2 |
hex | 12b5761a4e1 |
1285661238497 has 2 divisors, whose sum is σ = 1285661238498. Its totient is φ = 1285661238496.
The previous prime is 1285661238479. The next prime is 1285661238529. The reversal of 1285661238497 is 7948321665821.
Together with previous prime (1285661238479) it forms an Ormiston pair, because they use the same digits, order apart.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1203060179281 + 82601059216 = 1096841^2 + 287404^2 .
It is a cyclic number.
It is not a de Polignac number, because 1285661238497 - 224 = 1285644461281 is a prime.
It is not a weakly prime, because it can be changed into another prime (1285661238097) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 642830619248 + 642830619249.
It is an arithmetic number, because the mean of its divisors is an integer number (642830619249).
Almost surely, 21285661238497 is an apocalyptic number.
It is an amenable number.
1285661238497 is a deficient number, since it is larger than the sum of its proper divisors (1).
1285661238497 is an equidigital number, since it uses as much as digits as its factorization.
1285661238497 is an evil number, because the sum of its binary digits is even.
The product of its digits is 34836480, while the sum is 62.
The spelling of 1285661238497 in words is "one trillion, two hundred eighty-five billion, six hundred sixty-one million, two hundred thirty-eight thousand, four hundred ninety-seven".
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