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12866014101433 is a prime number
BaseRepresentation
bin1011101100111001101000…
…1100110011111110111001
31200112222102122101122201211
42323032122030303332321
53141244044102221213
643210322033443121
72465352552301453
oct273163214637671
950488378348654
1012866014101433
11411049a5a9019
12153962a1104a1
1372434c08b82c
14326a0b4372d3
15174a1b93653d
hexbb39a333fb9

12866014101433 has 2 divisors, whose sum is σ = 12866014101434. Its totient is φ = 12866014101432.

The previous prime is 12866014101389. The next prime is 12866014101443. The reversal of 12866014101433 is 33410141066821.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 6548291635369 + 6317722466064 = 2558963^2 + 2513508^2 .

It is a cyclic number.

It is not a de Polignac number, because 12866014101433 - 229 = 12865477230521 is a prime.

It is not a weakly prime, because it can be changed into another prime (12866014101443) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6433007050716 + 6433007050717.

It is an arithmetic number, because the mean of its divisors is an integer number (6433007050717).

Almost surely, 212866014101433 is an apocalyptic number.

It is an amenable number.

12866014101433 is a deficient number, since it is larger than the sum of its proper divisors (1).

12866014101433 is an equidigital number, since it uses as much as digits as its factorization.

12866014101433 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 82944, while the sum is 40.

The spelling of 12866014101433 in words is "twelve trillion, eight hundred sixty-six billion, fourteen million, one hundred one thousand, four hundred thirty-three".