Base | Representation |
---|---|
bin | 1011101101001111011011… |
… | …1011011101110100110011 |
3 | 1200120112112101112001221001 |
4 | 2323103312323131310303 |
5 | 3141343034342140421 |
6 | 43213130354342431 |
7 | 2465650544400343 |
oct | 273236673356463 |
9 | 50515471461831 |
10 | 12871864802611 |
11 | 4112a22126451 |
12 | 153a7a158aa17 |
13 | 724a722428a9 |
14 | 3270044a0d23 |
15 | 174c603cc691 |
hex | bb4f6eddd33 |
12871864802611 has 4 divisors (see below), whose sum is σ = 12872119001872. Its totient is φ = 12871610603352.
The previous prime is 12871864802597. The next prime is 12871864802627. The reversal of 12871864802611 is 11620846817821.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 12871864802611 - 223 = 12871856414003 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12871864802711) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 127023660 + ... + 127124953.
It is an arithmetic number, because the mean of its divisors is an integer number (3218029750468).
Almost surely, 212871864802611 is an apocalyptic number.
12871864802611 is a deficient number, since it is larger than the sum of its proper divisors (254199261).
12871864802611 is an equidigital number, since it uses as much as digits as its factorization.
12871864802611 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 254199260.
The product of its (nonzero) digits is 2064384, while the sum is 55.
The spelling of 12871864802611 in words is "twelve trillion, eight hundred seventy-one billion, eight hundred sixty-four million, eight hundred two thousand, six hundred eleven".
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