Base | Representation |
---|---|
bin | 11000000000100111… |
… | …00010110110111011 |
3 | 1020021022212010200021 |
4 | 30000103202312323 |
5 | 202344321303103 |
6 | 5531021551311 |
7 | 634266256663 |
oct | 140023426673 |
9 | 36238763607 |
10 | 12890025403 |
11 | 55150a0962 |
12 | 25b8a15537 |
13 | 12a5678088 |
14 | 8a3cdd1a3 |
15 | 50697bbbd |
hex | 3004e2dbb |
12890025403 has 8 divisors (see below), whose sum is σ = 12972384000. Its totient is φ = 12807843048.
The previous prime is 12890025361. The next prime is 12890025409. The reversal of 12890025403 is 30452009821.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 12890025403 - 213 = 12890017211 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12890025409) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 104268 + ... + 191446.
It is an arithmetic number, because the mean of its divisors is an integer number (1621548000).
Almost surely, 212890025403 is an apocalyptic number.
12890025403 is a deficient number, since it is larger than the sum of its proper divisors (82358597).
12890025403 is an equidigital number, since it uses as much as digits as its factorization.
12890025403 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 88121.
The product of its (nonzero) digits is 17280, while the sum is 34.
The spelling of 12890025403 in words is "twelve billion, eight hundred ninety million, twenty-five thousand, four hundred three".
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