Base | Representation |
---|---|
bin | 11000000001011111… |
… | …10100001001101011 |
3 | 1020021211210122110201 |
4 | 30000233310021223 |
5 | 202403220430032 |
6 | 5531444453031 |
7 | 634416254002 |
oct | 140057641153 |
9 | 36254718421 |
10 | 12897436267 |
11 | 55192a2841 |
12 | 25bb3aa177 |
13 | 12a70712c1 |
14 | 8a4cabc39 |
15 | 5074428e7 |
hex | 300bf426b |
12897436267 has 2 divisors, whose sum is σ = 12897436268. Its totient is φ = 12897436266.
The previous prime is 12897436247. The next prime is 12897436271. The reversal of 12897436267 is 76263479821.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12897436267 - 227 = 12763218539 is a prime.
It is a super-2 number, since 2×128974362672 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12897436217) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6448718133 + 6448718134.
It is an arithmetic number, because the mean of its divisors is an integer number (6448718134).
Almost surely, 212897436267 is an apocalyptic number.
12897436267 is a deficient number, since it is larger than the sum of its proper divisors (1).
12897436267 is an equidigital number, since it uses as much as digits as its factorization.
12897436267 is an evil number, because the sum of its binary digits is even.
The product of its digits is 6096384, while the sum is 55.
The spelling of 12897436267 in words is "twelve billion, eight hundred ninety-seven million, four hundred thirty-six thousand, two hundred sixty-seven".
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