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12906696365153 is a prime number
BaseRepresentation
bin1011101111010001001100…
…0011010101010001100001
31200200212102212020210002222
42323310103003111101201
53142430403232141103
643241130543520425
72501322652653353
oct273642303252141
950625385223088
1012906696365153
114126776691978
1215454a25b9115
137281335b0526
1432898a4830d3
15175aed28a638
hexbbd130d5461

12906696365153 has 2 divisors, whose sum is σ = 12906696365154. Its totient is φ = 12906696365152.

The previous prime is 12906696365119. The next prime is 12906696365191. The reversal of 12906696365153 is 35156369660921.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12067480973584 + 839215391569 = 3473828^2 + 916087^2 .

It is a cyclic number.

It is not a de Polignac number, because 12906696365153 - 214 = 12906696348769 is a prime.

It is a super-2 number, since 2×129066963651532 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12906696335153) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6453348182576 + 6453348182577.

It is an arithmetic number, because the mean of its divisors is an integer number (6453348182577).

Almost surely, 212906696365153 is an apocalyptic number.

It is an amenable number.

12906696365153 is a deficient number, since it is larger than the sum of its proper divisors (1).

12906696365153 is an equidigital number, since it uses as much as digits as its factorization.

12906696365153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 47239200, while the sum is 62.

The spelling of 12906696365153 in words is "twelve trillion, nine hundred six billion, six hundred ninety-six million, three hundred sixty-five thousand, one hundred fifty-three".