Base | Representation |
---|---|
bin | 10010110010011111001… |
… | …101100011101000100001 |
3 | 11120102201020210222121111 |
4 | 102302133031203220201 |
5 | 132123244244214334 |
6 | 2425052404023321 |
7 | 162166116065053 |
oct | 22623715435041 |
9 | 4512636728544 |
10 | 1291161319969 |
11 | 45863a9a5054 |
12 | 18a29b391b41 |
13 | 949a9baa661 |
14 | 466c77678d3 |
15 | 238bceb2064 |
hex | 12c9f363a21 |
1291161319969 has 2 divisors, whose sum is σ = 1291161319970. Its totient is φ = 1291161319968.
The previous prime is 1291161319949. The next prime is 1291161319997. The reversal of 1291161319969 is 9699131611921.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1221511248400 + 69650071569 = 1105220^2 + 263913^2 .
It is a cyclic number.
It is not a de Polignac number, because 1291161319969 - 213 = 1291161311777 is a prime.
It is a super-2 number, since 2×12911613199692 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1291161319949) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 645580659984 + 645580659985.
It is an arithmetic number, because the mean of its divisors is an integer number (645580659985).
Almost surely, 21291161319969 is an apocalyptic number.
It is an amenable number.
1291161319969 is a deficient number, since it is larger than the sum of its proper divisors (1).
1291161319969 is an equidigital number, since it uses as much as digits as its factorization.
1291161319969 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1417176, while the sum is 58.
The spelling of 1291161319969 in words is "one trillion, two hundred ninety-one billion, one hundred sixty-one million, three hundred nineteen thousand, nine hundred sixty-nine".
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